The diagonals of a parallelogram bisect each other.

Proposition:Let the diagonals AC and BD of the parallelogram ABCD intersect at O. It is required to prove that AO = CO, BO = DO.

Proof: Step-1: The lines AB and DC are parallel and AC is their transversal.
Therefore, ∠BAC = alternate ∠ACD. (Alternate angles are equal)

Step-2: The lines BC and AD are parallel and BD is their transversal
Therefore, ∠BDC = alternate ∠ABD. (Alternate angles are equal)

Step-3: Now, between ΔAOB and ΔCOD
∠OAB = ∠OCD, ∠OBA = ∠ODC and AB = DC .
Therefore, AO = CO and BO = DO. (Proved)

Digital STUDY Center

Digital Study Center offers an effective and amazing learning platform for keen learn students in the world. We identify the needs and demands of the keen learn students which is why we stand out unique in the crowd.

Post A Comment:


Dear readers,
Your feedback is usually appreciated. We'll reply to your queries among 24hrs. Before writing your comments, please read the the subsequent directions attentively:

1. Please comments in English. We accept only English comments.

2. Please don't Spam. All spammed comments will be deleted as before long as pobile, after review.

3. Please don't Add Links with your comments as they won't be published.

4. If We can be of assistance, please don't hesitate to contact us.